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Quadratic Equations
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June 15, 2021 10:29 am
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(@armor)
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Simply the following term

T=(\frac{a^2-b^2}{x^2-y^2})^n*(\frac{x-y}{a+b})^n.

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June 15, 2021 10:29 am
Topic starter
Staff 
(@armor)
Admin
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317 Posts
156 153 0

Applying power rules and the third binomial formula, we get

\small T=(\frac{(a^2-b^2)(x-y)}{(x^2-y^2)(a+b)})^n

\small =(\frac{(a-b)(a+b)(x-y)}{(x-y)(x+y)(a+b)})^n=(\frac{a-b}{x+y})^n.

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