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[Solved] Factorization

 
Quadratic Equations
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June 15, 2021 11:24 am
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Staff 
(@armor)
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x^2>y^2,

(x^2+1)^2-(y^2-3)^2=0\Rightarrow x^2+y^2=?

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June 15, 2021 11:24 am
Topic starter
Staff 
(@armor)
Admin
  Honorable Member
317 Posts
156 153 0

\small (x^2+1-y^2+3)(x^2+1+y^2-3)=0

\small (x^2-y^2+4)(x^2+y^2-2)=0

\small x^2-y^2=-4, x^2+y^2=2

\small x^2>y^2\rightarrow x^2-y^2\neq -4

\small \Rightarrow x^2+y^2=2.

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