June 15, 2021 4:31 pm
Topic starter
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In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
1 Answer
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June 15, 2021 4:31 pm
Topic starter
Total number of balls = 8 + 7 + 6 = 21.
Let E= event that the ball drawn is neither red nor green
= event that the ball drawn is blue
n(E)=7