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[Solved] Polynomial question

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der(P^2(x).Q(x))=8,

der(\frac{P(x)}{Q(x)})=1

\Rightarrow der(P(x)+Q(x))=?

 

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Topic starter

\small der(P(x))=p,   \small der(Q(x))=q,

\small der(P^2(x).Q(x))=2p+q=8

\small der(P(x)/Q(x))=p-q=1

\small \Rightarrow 3p=9\Rightarrow p=3,q=2.

\small der(P(x)+Q(x))=max(p,q)=3.

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