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[Solved] Exponential functions and polynomial solve the expression

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P(x^2)=x^4-1,

Q(\sqrt{x})=x+1

\Rightarrow P(x).Q(x)=?

A) x^4+1

B)x^4-1

C) x^2-1

D) x^2+1

 

1 Answer
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Topic starter

\small P(x^2)=(x^2)^2-1

\small P(x)=x^2-1,

\small Q(\sqrt{x^2})=x^2+1

\small Q(x)=x^2+1

\small \Rightarrow P(x).Q(x)=(x^2-1)(x^2+1)=x^4+x^2-x^2-1=x^4-1.

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